document.write( "Question 1077881: A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 40% and the third contains 85% . He wants to use all three solutions to obtain a mixture of 108 liters containing 45% acid, using 2 times as much of the 85% solution as the 40% solution. How many liters of each solution should be used?\r
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document.write( "The chemist should use _____ liters of 25% solution, _____ liters of 35% solution, and ____ liters of 75% solution.
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Algebra.Com's Answer #692411 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! The first acid solution contains 25% acid, the second contains 40% and the third contains 85% . He wants to use all three solutions to obtain a mixture of 108 liters containing 45% acid, using 2 times as much of the 85% solution as the 40% solution. How many liters of each solution should be used? \n" ); document.write( "--------------------------------------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "x of 25% \n" ); document.write( "y of 40% \n" ); document.write( "z of 85% \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "- \n" ); document.write( "Account for the pure acid \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Account for the volume \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simpler system in two variables: \n" ); document.write( "Use five times the second equation and subtract from first equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "- \n" ); document.write( "60 liters of 25% \n" ); document.write( "16 liters of 40% \n" ); document.write( "32 liters of 85% \n" ); document.write( " |