document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077813>Question 1077813</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Income (in Rands) of drivers during the week are 1080,2000,1540,1580,2500,1800,1580 find Quartile Deviation\r<BR>\n" );
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document.write( "Please correct me from my answering\r<BR>\n" );
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document.write( "Sol: step 1 rearrangement of numerical order<BR>\n" );
document.write( "1080,1540,1580,1580,1800,2000,2500\r<BR>\n" );
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document.write( "Let x equal to number of count \r<BR>\n" );
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document.write( "x=7\r<BR>\n" );
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document.write( "x=7/2=3.5<BR>\n" );
document.write( "1580 is the third value in Q1<BR>\n" );
document.write( "1540 is the second value in Q1 <BR>\n" );
document.write( "Q1=(1540+1580)/2= 1560<BR>\n" );
document.write( "Q1=1560\r<BR>\n" );
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document.write( "2000 is the second value in Q3<BR>\n" );
document.write( "2500 is the third value in Q3 <BR>\n" );
document.write( "Q3=(2000+2500)/2=2250<BR>\n" );
document.write( "Q3 = 2250\r<BR>\n" );
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document.write( "QD= (Q3-Q1)/2<BR>\n" );
document.write( "  = (2250-1560)/2<BR>\n" );
document.write( "  = 345\r<BR>\n" );
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document.write( "Therefore quartile deviation is 345 correct me if I am wrong </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692328 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there is more than one definition for quartiles.  Here, there is a median, so remove it and take the middle of the lower and upper three: that would be 1540 and 2000 for Q1 and Q3.  Q2, the median is 1580.\r<BR>\n" );
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document.write( "Others take the number of items and divide by 4, so 7/4 would be 3/4 of the way from the first to the second.  \r<BR>\n" );
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document.write( "I prefer taking the median of the lower half for Q1 and upper half for Q3.  The way you are doing it is taking the median of the lower 4 and the median of the upper 2, and that would not be correct.  Take the median of the distribution.  Then take the median of that.  This is always defensible.<BR>\n" );
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