document.write( "Question 1077722: there exist two circles that go through two points (1,3); (2,4) and are tangent to the y-axis. Letting the radii of the circles be a, b implies that ab=?
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Algebra.Com's Answer #692320 by ikleyn(52803)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The solution would be much easier to understand having a plot.
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document.write( "1.  Draw (mentally) the segment connecting the given points (1,3) and (2,4).\r\n" );
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document.write( "    This segment has the slope 1 = \"%284-3%29%2F%282-1%29\".\r\n" );
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document.write( "    The centers of the two circles lie in the perpendicular bisector to this segment.\r\n" );
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document.write( "    The perpendicular bisector goes through the middle point (1.5,3.5) and has the slope -1.\r\n" );
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document.write( "2.  Let us find the radius of the \"upper\" circle.\r\n" );
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document.write( "    Let \"p\" be the distance along the perpendicular bisector from the middle point (1.5,3.5) to the center of the \"upper\" circle.\r\n" );
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document.write( "    Then the center of the \"upper\" circle is at the point (\"1.5-p%2Fsqrt%282%29\",\"3.5%2Bp%2Fsqrt%282%29\"),  and   the radius of the upper circle is \"sqrt%28p%5E2+%2B+%281%2Fsqrt%282%29%29%5E2%29\".\r\n" );
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document.write( "    Since the upper circle touches y-axis, it gives the equation for \"p\"\r\n" );
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document.write( "        \"sqrt%28p%5E2+%2B+%281%2Fsqrt%282%29%29%5E2%29\" = \"1.5-p%2Fsqrt%282%29\".\r\n" );
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document.write( "    From this equation, p = (square both sides; simplify; then apply the quadratic formula) = \"sqrt%282%29%2F2\".\r\n" );
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document.write( "    Then the radius of the upper circle is  \"a%5E2\" = \"p%5E2+%2B+%281%2Fsqrt%282%29%29%5E2\" = 1,   which gives  a = 1.   (1)\r\n" );
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document.write( "3.  Now, let us find the radius of the \"lower\" circle.\r\n" );
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document.write( "    Let \"q\" be the distance along the perpendicular bisector from the middle point (1.5,3.5) to the center of the \"lower\" circle.\r\n" );
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document.write( "    Then the center of the \"lower\" circle is at the point (\"1.5%2Bq%2Fsqrt%282%29\",\"3.5-q%2Fsqrt%282%29\"),  and   the radius of the lower circle is \"sqrt%28q%5E2+%2B+%281%2Fsqrt%282%29%29%5E2%29\".\r\n" );
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document.write( "    Since the lower circle touches y-axis, it gives the equation for \"q\"\r\n" );
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document.write( "        \"sqrt%28q%5E2+%2B+%281%2Fsqrt%282%29%29%5E2%29\" = \"1.5%2Bq%2Fsqrt%282%29\".\r\n" );
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document.write( "    From this equation, q = (square both sides; simplify; then apply the quadratic formula) = \"7%2Asqrt%282%29%2F2\".\r\n" );
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document.write( "    Then the radius of the upper circle is  \"b%5E2\" = \"q%5E2+%2B+%281%2Fsqrt%282%29%29%5E2\" = \"100%2F4\" = 25,   which gives  b = \"sqrt%2825%29\" = 5.   (2)\r\n" );
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document.write( "3.  From (1) and (2), a*b = 1*5 = 5.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer. The product a*b under the question is 5.\r
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\n" ); document.write( "\n" ); document.write( "Now, finally, I use all that I got and illustrate these results in the plot below.\r
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