document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077800>Question 1077800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line that is tangent to the circle (x – 2)2 + (y – 4)2 = 289, at the point (-15, 4).\r<BR>\n" );
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document.write( "x = -15<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "y = 4<BR>\n" );
document.write( "y = -15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692319 by </B><A HREF=/tutors/aboutme.mpl?userid=MathLover1><B>MathLover1(20850)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathLover1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathLover1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the equation of the line that is tangent to the circle <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-2%29%5E2+%2B+%28y-4%29%5E2+=+289 ALIGN=MIDDLE  ALT=\"%28x-2%29%5E2+%2B+%28y-4%29%5E2+=+289\"   DISABLED_style= \"max-width:90%; height:auto;\" > is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=-15 ALIGN=MIDDLE  ALT=\"x=-15\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28+600%2C+600%2C+-30%2C+30%2C+-30%2C+30%2C%0D%0Aline%28-15%2C-25%2C-15%2C25%29%2C%0D%0A+graph%28+600%2C+600%2C+-30%2C+30%2C+-30%2C+30%2C+-sqrt%28289-%28x+-+2%29%5E2%29%2B4%2Csqrt%28289-%28x+-+2%29%5E2%29%2B4%29%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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