document.write( "Question 1077781: 9.2 #16
\n" ); document.write( "People were polled on how many books they read the previous year. Initial survey results indicate that s=17.7 books. Complete parts ​(a) through ​(d) below.\r
\n" ); document.write( "\n" ); document.write( "a) How many subjects are needed to estimate the mean number of books read the previous year within four books with 95​% ​confidence?\r
\n" ); document.write( "\n" ); document.write( "b) How many subjects are needed to estimate the mean number of books read the previous year within 2 books with 95​% ​confidence?\r
\n" ); document.write( "\n" ); document.write( "this confidence level requites how many subjects?\r
\n" ); document.write( "\n" ); document.write( "c) how many subjects are needed to estimate the mean number of books read the previous year within four books with 9% confidence?
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Algebra.Com's Answer #692284 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
interval is 1.96*s/sqrt(n). I will use z, as I suspect n is large. If not, I will iterate with t.
\n" ); document.write( "1.96*17.7/sqrt(n)=4
\n" ); document.write( "n=75.22 when squaring and rearranging.
\n" ); document.write( "Will use t=2
\n" ); document.write( "[2*17.7/4]^2=78.32 or 79.
\n" ); document.write( "This has a t=1.99
\n" ); document.write( "n=78
\n" ); document.write( "with 2 books, this will be a much higher sample size
\n" ); document.write( "313.29, round to 314, and z is used here.
\n" ); document.write( "For the last, I am going to assume 99% is meant.
\n" ); document.write( "use 2.576 for z
\n" ); document.write( "129.93 or 130 books.
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