document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077784>Question 1077784</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 meters less than twice the width. If the area of the rectangle is 464 square meters find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692277 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 2W-3<BR>\n" );
document.write( "2L+2W = 464<BR>\n" );
document.write( "2(2W-3)+2W = 464<BR>\n" );
document.write( "4W-6+2W = 464<BR>\n" );
document.write( "6W = 470<BR>\n" );
document.write( "W = 470/6 = 78.333<BR>\n" );
document.write( "L = 2W-3 = 2(78.333)-3 = 153.667<BR>\n" );
document.write( "--------------------------------<BR>\n" );
document.write( "check:<BR>\n" );
document.write( "2(153.667)+2(78.333) = 307.334+156.666 = 464 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );