document.write( "Question 1077779: The sum of two numbers that are at the ratio of 3:4 is 1001. Find these numbers. \n" ); document.write( "

Algebra.Com's Answer #692271 by MathLover1(20855) $\"\"$ $\"About$

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\n" ); document.write( "let's two numbers be $\"x\"$ and $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( "the ratio of $\"x\"$ to $\"y\"$ is $\"3%2F4\"$ : \r
\n" ); document.write( "\n" ); document.write( " $\"x%2Fy=3%2F4\"$ ......eq.1\r
\n" ); document.write( "\n" ); document.write( "and the sum of two numbers is $\"1001\"$ :\r
\n" ); document.write( "\n" ); document.write( " $\"x%2By=1001\"$ .........eq.2...solve for $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=1001-y\"$ .......eq.2a\r
\n" ); document.write( "\n" ); document.write( "substitute $\"x\"$ in eq.1\r
\n" ); document.write( "\n" ); document.write( " $\"%281001-y%29%2Fy=3%2F4\"$ ......eq.1.....solve for $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4%281001-y%29=3y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4004-4y=3y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4004=3y%2B4y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4004=7y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4004%2F7=y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=highlight%28572%29\"$ \r
\n" ); document.write( "\n" ); document.write( "go to $\"x=1001-y\"$ .......eq.2a, substitute $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=1001-572\"$
\n" ); document.write( " $\"x=highlight%28429%29\"$ \r
\n" ); document.write( "\n" ); document.write( "so, your numbers are: $\"highlight%28429%29\"$ and $\"highlight%28572%29\"$ \r
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