document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077750>Question 1077750</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 84 feet. If the length was increased by 3 feet and the width was doubled, the perimeter would be 120 feet. What are the dimensions of the rectangle?<BR>\n" );
document.write( "I spent hours on this problem please help!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692251 by </B><A HREF=/tutors/aboutme.mpl?userid=amfagge92><B>amfagge92(93)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amfagge92><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amfagge92><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SOLUTION<BR>\n" );
document.write( "PERIMETER OF RECTANGLE=2(l+b)<BR>\n" );
document.write( "2(l+b)=84...i<BR>\n" );
document.write( "2[(l+3)+2b)=120...ii<BR>\n" );
document.write( "solving<BR>\n" );
document.write( "l+b=42<BR>\n" );
document.write( "l=42-b...iii<BR>\n" );
document.write( "subtutute l in eqn ii<BR>\n" );
document.write( "l+3+2b=60<BR>\n" );
document.write( "42-b+3+2b=60<BR>\n" );
document.write( "b=15<BR>\n" );
document.write( "put b in eqn iii<BR>\n" );
document.write( "l=42-15=27<BR>\n" );
document.write( "Length =27, Breadth=15<BR>\n" );
document.write( "check:2(l+b)=84<BR>\n" );
document.write( "2(27+15)=84\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "check eqn ii yourself </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );