document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077755>Question 1077755</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A point (-2,-5) is on the terminal side of angle  &#952; when drawn in standard position. Find the exact value of each of the six trigonometric functions of   &#952;. <BR>\n" );
document.write( "Please help me to solve this. Thanks.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692248 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A point (-2,-5) is on the terminal side of angle  &#952; when drawn in standard position. Find the exact value of each of the six trigonometric functions of   &#952;. <BR>\n" );
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document.write( "Find radius, the distance from (0,0) to the point.<BR>\n" );
document.write( "r = sqrt(2^2 + 5^2) = sqrt(29)<BR>\n" );
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document.write( "sin = y/r = -2/sqrt(29)<BR>\n" );
document.write( "cos = x/r<BR>\n" );
document.write( "tan = y/x<BR>\n" );
document.write( "---<BR>\n" );
document.write( "cot = 1/tan<BR>\n" );
document.write( "sec = 1/cos<BR>\n" );
document.write( "csc = 1/sin<BR>\n" );
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