document.write( "Question 1077751: x + y = 16 x-y = 10 solve by substitution.\r
\n" ); document.write( "\n" ); document.write( "The answer sheet says (8,-2) I am coming up with something different. Please help!
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Algebra.Com's Answer #692234 by addingup(3677)\"\" \"About 
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By substitution:
\n" ); document.write( "x + y = 16 subtract y from both sides:
\n" ); document.write( "x = 16-y
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\n" ); document.write( "x-y = 10 here substitute for x:
\n" ); document.write( "16-y-y = 10
\n" ); document.write( "-2y = -6
\n" ); document.write( "y = 3 and since 16-y = x then 16-3 = x = 13
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\n" ); document.write( "by addition:
\n" ); document.write( "x+y = 16
\n" ); document.write( "x-y = 10
\n" ); document.write( "2x = 26
\n" ); document.write( "x = 13 and since x+y = 16, then 16-13 = y = 3
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\n" ); document.write( "As you see, your answer is (13, 3)\r
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