document.write( "Question 1077709: Find two consecutive integer such that the squares of the larger diminished by five times the smaller is equal to 71.
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Algebra.Com's Answer #692177 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x and x+1 \n" ); document.write( "(x+1)^2-5x=71 \n" ); document.write( "x^2+2x+1-5x=71 \n" ); document.write( "x^2-3x+1=71 \n" ); document.write( "x^2-3x-70=0 \n" ); document.write( "(x-10)(x+7)=0 \n" ); document.write( "x=10,-7 \n" ); document.write( "10 and 11 \n" ); document.write( "121-50=71, they work \n" ); document.write( "----------- \n" ); document.write( "-7 and -6 \n" ); document.write( "36-(-35)=71, they work\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |