document.write( "Question 1077709: Find two consecutive integer such that the squares of the larger diminished by five times the smaller is equal to 71.
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Algebra.Com's Answer #692177 by Boreal(15235)\"\" \"About 
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x and x+1
\n" ); document.write( "(x+1)^2-5x=71
\n" ); document.write( "x^2+2x+1-5x=71
\n" ); document.write( "x^2-3x+1=71
\n" ); document.write( "x^2-3x-70=0
\n" ); document.write( "(x-10)(x+7)=0
\n" ); document.write( "x=10,-7
\n" ); document.write( "10 and 11
\n" ); document.write( "121-50=71, they work
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\n" ); document.write( "-7 and -6
\n" ); document.write( "36-(-35)=71, they work\r
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