document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077685>Question 1077685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Recall that two angles are complementary if the sum of their measures is 90°. Find the measures of two complementary angles if one angle is twice the other.\r<BR>\n" );
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document.write( "All I have been able to come up with is: x+y=90. And x=2y.  However it doesn't make sense. Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692152 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692152\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the measures of two complementary angles if one angle is twice the other.\r<BR>\n" );
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document.write( "All I have been able to come up with is: x+y=90. And x=2y.  However it doesn't make sense. Please help!<BR>\n" );
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document.write( "x+y=90.<BR>\n" );
document.write( "And x=2y<BR>\n" );
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document.write( "Sub for x in the 1st equation<BR>\n" );
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document.write( "2y + y = 90<BR>\n" );
document.write( "3y = 90<BR>\n" );
document.write( "y = 30<BR>\n" );
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document.write( "x = 60\r<BR>\n" );
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document.write( " </SPAN>\n" );
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