document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077666>Question 1077666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help with p value, I entered tcdf(1.063,99,7), not working!<BR>\n" );
document.write( "In this problem, assume that the distribution of differences is approximately normal. Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this choice of d.f. may increase the P-value by a small amount and therefore produce a slightly more \"conservative\" answer.\r<BR>\n" );
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document.write( "Are America's top chief executive officers (CEOs) really worth all that money? One way to answer this question is to look at row B, the annual company percentage increase in revenue, versus row A, the CEO's annual percentage salary increase in that same company. Suppose a random sample of companies yielded the following data:<BR>\n" );
document.write( "B: Percent increase<BR>\n" );
document.write( "for company	28	22	26	18	6	4	21	37<BR>\n" );
document.write( "A: Percent increase<BR>\n" );
document.write( "for CEO	15	19	28	14	-4	19	15	30<BR>\n" );
document.write( "Do these data indicate that the population mean percentage increase in corporate revenue (row B) is different from the population mean percentage increase in CEO salary? Use a 5% level of significance.<BR>\n" );
document.write( "(a) What is the level of significance?<BR>\n" );
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document.write( ".05<BR>\n" );
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document.write( "Correct: Your answer is correct.<BR>\n" );
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document.write( "State the null and alternate hypotheses.<BR>\n" );
document.write( "H0: &#956;d = 0; H1: &#956;d > 0<BR>\n" );
document.write( "H0: &#956;d = 0; H1: &#956;d < 0    <BR>\n" );
document.write( "H0: &#956;d > 0; H1: &#956;d = 0<BR>\n" );
document.write( "H0: &#956;d &#8800; 0; H1: &#956;d = 0<BR>\n" );
document.write( "H0: &#956;d = 0; H1: &#956;d &#8800; 0<BR>\n" );
document.write( "Correct: Your answer is correct.\r<BR>\n" );
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document.write( "(b) What sampling distribution will you use? What assumptions are you making?<BR>\n" );
document.write( "The standard normal. We assume that d has an approximately uniform distribution.<BR>\n" );
document.write( "The Student's t. We assume that d has an approximately uniform distribution.    <BR>\n" );
document.write( "The Student's t. We assume that d has an approximately normal distribution.<BR>\n" );
document.write( "The standard normal. We assume that d has an approximately normal distribution.<BR>\n" );
document.write( "Correct: Your answer is correct.\r<BR>\n" );
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document.write( "What is the value of the sample test statistic? (Round your answer to three decimal places.)<BR>\n" );
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document.write( "1.063<BR>\n" );
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document.write( "Correct: Your answer is correct.<BR>\n" );
document.write( " \r<BR>\n" );
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document.write( "(c) Find the P-value. (Round your answer to four decimal places.)<BR>\n" );
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document.write( ".1615<BR>\n" );
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document.write( "Incorrect: Your answer is incorrect.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692124 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692124\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are three possibilities.<BR>\n" );
document.write( "When I use a calculator, I get a t-statistic of 0.61, which is not the 1.063 called correct.  My p-value is 0.5536, which is quite different as well.<BR>\n" );
document.write( "The other issue is that the df=14 in this test, which doesn't change the p-value a lot, but does change it to about 0.1529.<BR>\n" );
document.write( "A third possibility, and the most important, is that a one way p-value has to be doubled for a two way test.  This is a 2-way test as I interpret it, so the amount goes on both sides of the curve, and the p-value would be 0.3230. The calculator and the table give the right hand interval only using the numbers provided.  </SPAN>\n" );
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