document.write( "Question 1077660: The amount a spring will stretch varies directly with the mass attached to the spring. The spring stretches 12
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\n" ); document.write( "a. Create an equation that represents the relationship.
\n" ); document.write( "b. Create a labelled diagram of the relationship. Which variable is the dependent variable?
\n" ); document.write( "c. How far will it stretch when 11 kg is attached?
\n" ); document.write( "d. If a mass is attached to the spring and it stretches 42 cm, how much mass was there?
\n" ); document.write( "e. Why does it make sense that this relationship is direct variation?
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Algebra.Com's Answer #692117 by Boreal(15235)\"\" \"About 
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y=kx, where y is spring stretching in cm and x is weight in kg
\n" ); document.write( "12=8k
\n" ); document.write( "k=1.5
\n" ); document.write( "use that in next part
\n" ); document.write( "y=1.5*11=16.5cm.
\n" ); document.write( "42=1.5*x
\n" ); document.write( "x=28 kg
\n" ); document.write( "it makes sense there is direct variation, because increased weight causes increased stretch. The only concern one might have is whether it is exponential, but it is not.
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