document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077627>Question 1077627</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If one of the quadratic equation px^+15-14=0 is 2/3 find the value of p and other root </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692089 by </B><A HREF=/tutors/aboutme.mpl?userid=amfagge92><B>amfagge92(93)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amfagge92><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amfagge92><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the other root be x<BR>\n" );
document.write( "sum of the roots =<BR>\n" );
document.write( "2/3+x=-15/p<BR>\n" );
document.write( "solving<BR>\n" );
document.write( "2p + 3xp=-45 as eqn (i)<BR>\n" );
document.write( " <BR>\n" );
document.write( "product of the root=<BR>\n" );
document.write( "2/3*x=-14/p as eqn (ii)<BR>\n" );
document.write( "gives<BR>\n" );
document.write( "xp=-21<BR>\n" );
document.write( " put xp in eqn (i)<BR>\n" );
document.write( "2p +3(-21)=-45<BR>\n" );
document.write( "2p-63=-45<BR>\n" );
document.write( "p=9\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( "hence,the other root is -7/3 using  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=B+=+%28-b+-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"B+=+%28-b+-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );