document.write( "Question 1077610: I cannot figure out how to get how many tickets were sold for each priced ticket. \r
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document.write( "A basketball team sells tickets that cost $10, $20, or, for VIP seats, $30. The team has sold 3343 tickets overall. It has sold 113 more $20 tickets than $10 tickets. The total sales for $62,350. How many tickets have been sold?
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document.write( "How many $10 tickets were sold?
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document.write( "How many $20 tickets were sold?
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document.write( "How many $30 tickets were sold? \n" );
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Algebra.Com's Answer #692065 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! x, how many $10 tickets \n" ); document.write( "y, how many $20 tickets \n" ); document.write( "z, how many $30 VIP tickets\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Follow the description. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Three linear equations in three unknown variables, so solve the system. \n" ); document.write( "You would want to simplify the sales equation to \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Work with THIS system: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "One path to begin can be, add first and second equations to form a new equation; and add the second and third equations to form another new equation. This eliminates x, and your two new equations are in just the two variables, y and z. \n" ); document.write( " |