document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077601>Question 1077601</A>: <I><SPAN STYLE=\"word-break: break-all;\"> you buy computer for$ 150. the computers value decreased by 12.5 % each year.<BR>\n" );
document.write( "write an exponential function for the value of the computer ?<BR>\n" );
document.write( "to the nearst tenth of a year when the computer be worth $600?<BR>\n" );
document.write( "to the nearst con, how much will the computer be worth in 10 years? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692056 by </B><A HREF=/tutors/aboutme.mpl?userid=themasterofcircuits><B>themasterofcircuits(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=themasterofcircuits><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=themasterofcircuits><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692056\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> V=V_0*e^(-k*t)<BR>\n" );
document.write( "Where V_0 is the initial value of the computer, k is the depreciation constant, and t is the number of years.\r<BR>\n" );
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document.write( "In this case, V_0 is $150 and k is 12.5% or 0.125\r<BR>\n" );
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document.write( "so [V=150*exp(-0.125*t)]\r<BR>\n" );
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document.write( " The max value of V is $150, so the computer will only go down in price as the years go down, so the value of the computer will [NEVER] reach $600.\r<BR>\n" );
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document.write( "In 10 years: V(10)=150*exp(-0.125*10)= [$42.97] </SPAN>\n" );
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