document.write( "Question 1077594: Jimbob is three years older than his brother. The sum of their ages is 33 how old is jimbob \n" ); document.write( "
Algebra.Com's Answer #692053 by themasterofcircuits(27)![]() ![]() You can put this solution on YOUR website! Let J represent Jimbob's age and B represent his brother's age:\r \n" ); document.write( "\n" ); document.write( "Jimbob is 3 years older than his brother, so J=B+3 \n" ); document.write( "The sum of Jimbob's age and his brother's age is 33, so J+B=33\r \n" ); document.write( "\n" ); document.write( "We now have a system of equations: \n" ); document.write( "J=B+3 (1) \n" ); document.write( "J+B=33 (2)\r \n" ); document.write( "\n" ); document.write( "Substitute (1) into (2):\r \n" ); document.write( "\n" ); document.write( "(B+3)+B=33 \n" ); document.write( "2B=30 \n" ); document.write( "[B=15] \n" ); document.write( "His brother is 15 years old.\r \n" ); document.write( "\n" ); document.write( "Substitute B=15 into (2) \n" ); document.write( "J+15=33 \n" ); document.write( "[J=18]\r \n" ); document.write( "\n" ); document.write( "Hence Jimbob is 18 years old and his brother is 15 years old. \n" ); document.write( " |