document.write( "Question 1077602: An angle measures 124° more than the measure of a supplementary angle. What is the measure of each angle?
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Algebra.Com's Answer #692050 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Two angles,\"alpha\" and \"beta\", are supplementary when they add up to \"180\" degrees.\r
\n" ); document.write( "\n" ); document.write( "\"alpha%2Bbeta=180\"....eq.1\r
\n" ); document.write( "\n" ); document.write( "if an angle (let's say \"alpha\") measures \"124\"° more than the measure of a supplementary angle (\"beta\"), we know that
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\n" ); document.write( "\"alpha=beta+%2B124\".....eq.2\r
\n" ); document.write( "\n" ); document.write( "substitute \"alpha\" from eq.2 in eq.1\r
\n" ); document.write( "\n" ); document.write( "\"beta+%2B124%2Bbeta=180\"....eq.1\r
\n" ); document.write( "\n" ); document.write( "\"2beta=180-124\"\r
\n" ); document.write( "\n" ); document.write( "\"2beta=56\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=56%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=28\"°\r
\n" ); document.write( "\n" ); document.write( "and,\"alpha=beta+%2B124\"=>\"alpha=28+%2B124\"=>\"alpha=152\"°\r
\n" ); document.write( "\n" ); document.write( "so, your supplementary angles are:\"152\"° and \"28\"°\r
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