document.write( "Question 1077585: The distance a person falls on a bungee chord in metres, h may be modelled with time, t in seconds according to:
\n" ); document.write( "h=2(t-5)^2-50
\n" ); document.write( "What is the greatest distance a person will reach on the bungee chord from their starting position? \n" ); document.write( "

Algebra.Com's Answer #692042 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "The distance a person falls on a bungee chord in meters, $\"h\"$ may be modeled with time, $\"t\"$ in seconds according to: \r
\n" ); document.write( "\n" ); document.write( " $\"h=2%28t-5%29%5E2-50+\"$ \r
\n" ); document.write( "\n" ); document.write( "What is the greatest distance a person will reach on the bungee chord from their starting position? \r
\n" ); document.write( "\n" ); document.write( "recall: The $\"maximum\"$ distance the bungee jumper falls corresponds to the $\"lowest\"$ point in the fall. \r
\n" ); document.write( "\n" ); document.write( "in your case, $\"h=2%28t-5%29%5E2-50+\"$ , we have an upside-down parabola because the leading coefficient is negative, and its $\"lowest\"$ point is $\"h%5B1%5D%2Ck+\"$ (I put $\"h%5B1%5D\"$ to make it different from distance $\"h\"$ ) which is its vertex\r
\n" ); document.write( "\n" ); document.write( "equation in vertex form $\"h=a%28t-h%5B1%5D%29%5E2%2Bk+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"h=2%28t-5%29%5E2-50+\"$ since you are given in vertex form, you see that $\"h%5B1%5D=5\"$ and $\"k=-50\"$ \r
\n" ); document.write( "\n" ); document.write( "so, the vertex is at ( $\"5\"$ , $\"-50\"$ ) and the greatest distance a person will reach on the bungee chord from their starting position is $\"h=-50\"$ \r
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