document.write( "Question 1077582: The two engine plane and a Boeing jet take off from an airport at the same time for a city 720 miles away. The rate of the two engine plane is 180 mi/h less than that of the Boeing jet. If the Boeing jet arrives 2 hours ahead of the two engine plane, find each planes rate. \n" ); document.write( "

Algebra.Com's Answer #692033 by jorel1380(3719) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let n be the speed of the small plane. Then the jet flies at n+180. So:
\n" ); document.write( "720/n=720/n+180 +2
\n" ); document.write( "720(n+180)=720n+2n²+360n
\n" ); document.write( "2n²+360n-129600=0
\n" ); document.write( "n²+180n-64800=0
\n" ); document.write( "(n+360)(n-180)=0
\n" ); document.write( "n=-360 or 180
\n" ); document.write( "Using the positive value, we get the speed of the two engine plane to be 180 mph, and that of the jet to be 360 mph. ☺☺☺☺ \n" ); document.write( "

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