document.write( "Question 1077519: Given that 3^-n = 0.2.
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Algebra.Com's Answer #692000 by MathLover1(20850)\"\" \"About 
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Given that
\n" ); document.write( "\"3%5E%28-n%29+=+0.2\"........solve for \"n\"\r
\n" ); document.write( "\n" ); document.write( "\"1%2F3%5En+=+2%2F10\"\r
\n" ); document.write( "\n" ); document.write( "\"1%2F3%5En+=+1%2F5\" =>if nominators same, denominators are same too\r
\n" ); document.write( "\n" ); document.write( "\"3%5En+=+5\"...........take log of both sides\r
\n" ); document.write( "\n" ); document.write( "\"log%283%5En%29+=+log%285%29\"\r
\n" ); document.write( "\n" ); document.write( "\"n%2Alog%283%29+=+log%285%29\"\r
\n" ); document.write( "\n" ); document.write( "\"n+=+log%285%29%2Flog%283%29\"\r
\n" ); document.write( "\n" ); document.write( "\"n+=+1.46497\"\r
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\n" ); document.write( "\n" ); document.write( "Find the value of \"%283%5E4%29%5En=3%5E%284n%29+\":\r
\n" ); document.write( "\n" ); document.write( "\"%283%29%5E%284%2A1.46497%29+=624.99=625\"\r
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