document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077465>Question 1077465</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A shipment of 50 television sets contains 3 defective units. How many ways can a vending company buy three of these units and receive no defective units?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691980 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One way is 47/50*46/49*45/48 and multiply by the number of possible ways to choose 3, which is 50C3.<BR>\n" );
document.write( "A little better way is to say there are 47 good ones and you want to know how many ways you can choose from 47. <BR>\n" );
document.write( "47C3=16215  ANSWER<BR>\n" );
document.write( "Using the probability above, unrounded, (rounded is 0.8273), 16215 is again reached. </SPAN>\n" );
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