document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077484>Question 1077484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a baseball team has 3 catchers, 9 pitchers, 6 infielders, and 7 outfielders. in how many ways can a team of 9 be chosen for a game? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691970 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691970\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 ways to choose a catcher<BR>\n" );
document.write( "9 ways to choose a pitcher<BR>\n" );
document.write( "6C4 ways to choose an infielder.  I erred here the first time. 6C4=6*5/2=15<BR>\n" );
document.write( "7C3 ways to choose an outfielder, which is 7*6*5*4!/4!3!, and that is 35 ways<BR>\n" );
document.write( "So it is 3*9*15*35=14,175.<BR>\n" );
document.write( "I erred in that there are 6 infielders that have to be used to fill 4 positions and 7 outfielders that have to be used to fill 3 positions.  The first two are straight multiplication.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );