document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95097>Question 95097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I really need help with this....PLEASE, PLEASE\r<BR>\n" );
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document.write( "2^8 times 2^-11\r<BR>\n" );
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document.write( "For this I just added the exponents and I got \r<BR>\n" );
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document.write( "2 to the negative 3rd power.\r<BR>\n" );
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document.write( "Because I have 2 to the 8th power, times 2 to the negative 11th power, I just added the exponents of 8+(-11) and I got the answer of 2 to the negative 3rd power. Is this right?\r<BR>\n" );
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document.write( "PLEASE HELP ME. I don't understand this question\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69196 by </B><A HREF=/tutors/aboutme.mpl?userid=ionesco><B>ionesco(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ionesco><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2^8 times 2^-11 = 2^-3=1/8 </SPAN>\n" );
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