document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077416>Question 1077416</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 93 square meters. If the length is 2 times the width, then find the dimensions of the rectangle. Round off your answers to the nearest hundredth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691952 by </B><A HREF=/tutors/aboutme.mpl?userid=Herdaysoji><B>Herdaysoji(25)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Herdaysoji><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Herdaysoji><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area is 93=length*width<BR>\n" );
document.write( "length=2*width<BR>\n" );
document.write( "93=2*width*width<BR>\n" );
document.write( "93=2(width)^2<BR>\n" );
document.write( "so, 93/2=width^2<BR>\n" );
document.write( "46.5=width^2<BR>\n" );
document.write( "width=root 46.5<BR>\n" );
document.write( "width=6.8190.....<BR>\n" );
document.write( "round off to 6.82<BR>\n" );
document.write( "length=2*6.82=13.64 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );