document.write( "Question 1077455: A basketball team sells tickets that cost $10, $20, and VIP seats for $30. The team has sold 3408 tickets overall. It has sold 129 more $20 tickets than $10 tickets. The total sales are $64,460. How many $10 tickets, $20 tickets, and $30 tickets have been sold?\r
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Algebra.Com's Answer #691945 by ikleyn(52787) $\"\"$ $\"About$

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document.write( "Let x be the number of $10 tickets, and let y be the number of $30 tickets.\r\n" );
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document.write( "Then the number of $20 tickets is (x+129).\r\n" );
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document.write( "The system of two equations in two unknowns is\r\n" );
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document.write( "x + (x+129) + y = 3408.         (1)    (The total number of tickets)\r\n" );
document.write( "10x + 20(x+129) + 30y = 64460   (2)   (The total sales)\r\n" );
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document.write( "Simplify and solve.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The lesson to learn from his solution: \r
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document.write( "     This problem reduces to two unknowns.\r\n" );
document.write( "     It is not about 3 unknowns.\r\n" );
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