document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077370>Question 1077370</A>: <I><SPAN STYLE=\"word-break: break-all;\">  the length of a rectangular floor is 1 meter less than three times its width if a diagonal of the rectangle is 37 meters find the length of the floor </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691941 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w be the width of the floor. Then its length is 3w-1. So:<BR>\n" );
document.write( "w²+(3w-1)²=37²<BR>\n" );
document.write( "w²+9w²-6w+1=1369<BR>\n" );
document.write( "10w²-6w-1368=0<BR>\n" );
document.write( "5w²-3w-684=0<BR>\n" );
document.write( "(5w+57)(w-12)=0<BR>\n" );
document.write( "w=-57/5 or 12<BR>\n" );
document.write( "Using the positive value of 12m for the width, we get the length to be 35m. &#9786;&#9786;&#9786;&#9786;<BR>\n" );
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