document.write( "Question 1077439: A piece of metal has the shape of a right triangle. The hypotenuse is 3 ft shorter than four times the shortest side and the longer side is 10 ft longer than twice the shorter side. What is the length of the hypotenuse of the​ triangle?
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Algebra.Com's Answer #691901 by Boreal(15235)\"\" \"About 
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shorter side=x
\n" ); document.write( "longer side is 2x+10
\n" ); document.write( "hypotenuse is 4x-3
\n" ); document.write( "square them all
\n" ); document.write( "x^2+(2x+10)^=(4x-3)^2. Note, binomial expansion (a+b)^2=a^2+2 ab (the internal products are doubled)+b^2
\n" ); document.write( "x^4x^2+40x+100=16x^2-24x+9
\n" ); document.write( "5x^2+40x+100=16x^2-24x+9
\n" ); document.write( "0=11x^2-64x-91
\n" ); document.write( "x=(1/22)(64+/- sqrt (4096+4004); sqrt 8100=90
\n" ); document.write( "x=(1/22)(64+/-90), use only the + root.
\n" ); document.write( "x=(1/22)154=7
\n" ); document.write( "sides are 7, 24, with hypotenuse 25, a well known right triangle.
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