document.write( "Question 1077369: the perimeter of a rectangle is 40 inches and its area is 91 square inches find the length and width of the rectangle. solve step by step. There are 10 steps \n" ); document.write( "
Algebra.Com's Answer #691833 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! 2L + 2W = 40 (1) —> L+W=20 \n" ); document.write( "LW = 91 (2)\r \n" ); document.write( "\n" ); document.write( "L = 91/W —> Substitute this into (1): \n" ); document.write( "(91/W) + W = 20 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "W=7 or W=13 \n" ); document.write( "W=7 —> L=13 \n" ); document.write( "W=13 —> L=7 (let's reject this as L>W is the convention when describing rectangles) \n" ); document.write( "— \n" ); document.write( "Ans: L=13in, W=7in \n" ); document.write( "— \n" ); document.write( "Check: Area = LxW = 13in*7in = 91 sq in (ok) \n" ); document.write( " Perimeter = 2L+2W=2(13in) + 2(7in) = 26in+14in = 40in (ok) \n" ); document.write( "— \n" ); document.write( " \n" ); document.write( " |