document.write( "Question 1077369: the perimeter of a rectangle is 40 inches and its area is 91 square inches find the length and width of the rectangle. solve step by step. There are 10 steps \n" ); document.write( "
Algebra.Com's Answer #691833 by math_helper(2461)\"\" \"About 
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2L + 2W = 40 (1) —> L+W=20
\n" ); document.write( "LW = 91 (2)\r
\n" ); document.write( "\n" ); document.write( "L = 91/W —> Substitute this into (1):
\n" ); document.write( "(91/W) + W = 20
\n" ); document.write( "\"91%2BW%5E2+=+20W+\" <— multiplied both sides by W
\n" ); document.write( "\"+W%5E2-20W%2B91+=+0+\"
\n" ); document.write( "\"+%28W-13%29%28W-7%29+=+0+\"
\n" ); document.write( "W=7 or W=13
\n" ); document.write( "W=7 —> L=13
\n" ); document.write( "W=13 —> L=7 (let's reject this as L>W is the convention when describing rectangles)
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\n" ); document.write( "Ans: L=13in, W=7in
\n" ); document.write( "—
\n" ); document.write( "Check: Area = LxW = 13in*7in = 91 sq in (ok)
\n" ); document.write( " Perimeter = 2L+2W=2(13in) + 2(7in) = 26in+14in = 40in (ok)
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