document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077272>Question 1077272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi can someone help me with this problem please? THANK YOU! \r<BR>\n" );
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document.write( "   Find a decimal approximation (to four decimal places) for unit circle point that is on the terminal side of the following angle in standard position. Hint:use the definitions of the circular functions. <BR>\n" );
document.write( "        Theta=251degrees <BR>\n" );
document.write( "      <BR>\n" );
document.write( "          a.(-0.9455,-0.3256)<BR>\n" );
document.write( "          b.(0.3256,0.9455)<BR>\n" );
document.write( "          c.(0.9455,0.3256)<BR>\n" );
document.write( "          d.(-0.3256,-0.9455) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691800 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691800\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=theta=251%5Eo+ ALIGN=MIDDLE  ALT=\"theta=251%5Eo+\"   DISABLED_style= \"max-width:90%; height:auto;\" > ==> angle terminates in Q3\r<BR>\n" );
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document.write( "All of the points are on the unit circle.  However, only (a) and (d) are in Q3.\r<BR>\n" );
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document.write( "The x-coordinate is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+r%2Acos%28theta%29+ ALIGN=MIDDLE  ALT=\"+r%2Acos%28theta%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and r=1 for the unit circle:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28251%5Eo%29+=+-0.3256+ ALIGN=MIDDLE  ALT=\"cos%28251%5Eo%29+=+-0.3256+\"   DISABLED_style= \"max-width:90%; height:auto;\" >  —>   (d) is the answer. </SPAN>\n" );
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