document.write( "Question 95066: The path of a falling object is given by the function s=16t^2+v0t+s0 where Vo represents the initial velocity in ft/sec and s0 represents the initial heigth in feet. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If a rock is throne upward with an initial velocity of 64 ft per sec. from the top of a 25 ft building, write the height (s) equation using this information.\r
\n" ); document.write( "\n" ); document.write( "a) how high is the rock after 1 sec?\r
\n" ); document.write( "\n" ); document.write( "b)after how many sec will the graph reach max heigth?\r
\n" ); document.write( "\n" ); document.write( "c) what is the max. heigth? \n" ); document.write( "
Algebra.Com's Answer #69173 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The path of a falling object is given by the function s=16t^2+v0t+s0 where Vo represents the initial velocity in ft/sec and s0 represents the initial height in feet.\r
\n" ); document.write( "\n" ); document.write( "If a rock is throne upward with an initial velocity of 64 ft per sec. from the top of a 25 ft building, write the height (s) equation using this information.
\n" ); document.write( ":
\n" ); document.write( "s = -16t2 + 64t + 25
\n" ); document.write( ":
\n" ); document.write( "Reviewing the Three parts of this equation
\n" ); document.write( "-16t^2 is the force of gravity, hence it is negative
\n" ); document.write( "64t is the initial upward velocity, it is positive
\n" ); document.write( "25 is the initial height of the building where this starts
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "a) how high is the rock after 1 sec?
\n" ); document.write( "Substitute 1 for t in the above equation and find s:
\n" ); document.write( "s = -16(1^2) + 64(1) + 25
\n" ); document.write( "s = -16 + 64 + 25
\n" ); document.write( "s = 73 ft above ground after 1 second
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "b)after how many sec will the graph reach max height?
\n" ); document.write( ":
\n" ); document.write( "Max height will occur at the axis of symmetry of this equation:
\n" ); document.write( ":
\n" ); document.write( "Formula for that is: x = -b/(2a)
\n" ); document.write( ":
\n" ); document.write( "In our equation this would be:
\n" ); document.write( "s = -64/(2*-16)
\n" ); document.write( "s = -64/-32
\n" ); document.write( "s = +2 seconds to reach max height
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "c) what is the max. height?
\n" ); document.write( "Find the this by substituting 2 for t in the equation:
\n" ); document.write( "s = -16(2^2) + 64(2) + 25
\n" ); document.write( "s = -16(4) + 128 + 25
\n" ); document.write( "s = -64 + 128 + 25
\n" ); document.write( "s = 89 ft is the max height occurring after 2 second
\n" ); document.write( ":
\n" ); document.write( "A graphical presentation would show this clearly.
\n" ); document.write( "x axis in seconds and y axis in feet
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-2%2C+8%2C+-20%2C+100%2C+-16x%5E2+%2B+64x+%2B+25%29+\"
\n" ); document.write( ":
\n" ); document.write( "Note after 1 sec it looks like it is about 70 ft and after 2 sec it's over 88 ft
\n" ); document.write( ":
\n" ); document.write( "Did I succeed in making this understandable to you?
\n" ); document.write( " \n" ); document.write( "
\n" );