document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077168>Question 1077168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x=log(20)+2  I need to find the exponential form of this equation. I know 20 is on one side of the equation but i'm not sure what I do with the +2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691704 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691704\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log 20=x-2<BR>\n" );
document.write( "raise everything to the 10 power<BR>\n" );
document.write( "10^log 20=20<BR>\n" );
document.write( "20=10^(x-2)<BR>\n" );
document.write( "20=10^x/100, or 10^2.<BR>\n" );
document.write( "10^x=2000, an exponential form<BR>\n" );
document.write( "x=3.3013\r<BR>\n" );
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