document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077167>Question 1077167</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Web invested 1750 in an account earning 13.5% interest compounded monthly for a 2 year period. What is the balance to the nearest dollar at the end of the 2 years<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691695 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691695\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Po{1+.135/12}^24, the 24 being the number of compoundings<BR>\n" );
document.write( "The parentheses is 1.308, but don't round until after multiplying by P0=$1750<BR>\n" );
document.write( "=$2288.98<BR>\n" );
document.write( "Check by comparing it to continuously compounding, which should be a little more.<BR>\n" );
document.write( "Poe^(.135*2)=$2292.43 </SPAN>\n" );
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