document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077130>Question 1077130</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A houseboat on a river traveled 48km upstream in 6h. It took the houseboat only 4h to make the same trip downstream.\r<BR>\n" );
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document.write( "a) How fast would the houseboat have traveled in still water?\r<BR>\n" );
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document.write( "b) How fast was the river's current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691680 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691680\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let b be the speed of the boat in still water, and c be the speed of the current. Then:<BR>\n" );
document.write( "48/b+c=4<BR>\n" );
document.write( "48/b-c=6<BR>\n" );
document.write( "So:<BR>\n" );
document.write( "4b+4c=48<BR>\n" );
document.write( "6b-6c=48<BR>\n" );
document.write( "12b+12c=144<BR>\n" );
document.write( "12b-12c=96<BR>\n" );
document.write( "24b=240<BR>\n" );
document.write( "b=10<BR>\n" );
document.write( "c=2<BR>\n" );
document.write( "The boat travels 10 kph in still water, and the current is 2 kph. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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