document.write( "Question 1077085: solve 3log_(5)y-log_(y)5=2 \n" ); document.write( "
Algebra.Com's Answer #691651 by Theo(13342) You can put this solution on YOUR website! this winds up being able to solve a quadratic equation. \n" ); document.write( "the math is horrendous, but i used an online quadratic equation calculator to solve to the degree of accuracy required.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the concept is as follows:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "start with 3log5(y) - logy(5) = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "conver to base of 10 log as follows:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log5(y) = log(6)/log(5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "logy(5) = log(5)/log(y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "equation becomes 3log(y)/log(5) - log(5)/log(y) = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(anything) is assumeed to be log10(anything).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your calculator can handle log10(anything) by use of the calculator LOG function.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so your equation has become:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3log(y)/log(5) - log(5)/log(y) = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of this equation by log(5)log(y) to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3log(y)^2 - log(5)^2 = 2log(5)log(y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 2log(5)log(y) from both sides of the equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3log(y)^2 - 2log(5)log(y) - log(5)^2 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let x = log(y).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "equation becomes 3x^2 - 2log(5)x - log(5)^2 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is a quadratic equation that can be solved by using the quadratic formula.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i spared myself the drudgery by using the following online quadratic equation solver:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "https://www.mathsisfun.com/quadratic-equation-solver.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since this solver couldn't handle -2log(5) or -log(5)^2, i had to convert them to fractions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-2log(5) became -1.397940009\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-log(5)^2 became -.48859067\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "these were input into the quadratic solve and the result was:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 0.69897000443178 or x = -0.23299000143178\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since x is equal to log(y), then the solution became:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(y) = 0.69897000443178 or log(y) = -0.23299000143178\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(y) = 0.69897000443178 if and only if 10^0.69897000443178 = y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this led to y = 5.000000001 or y = .5848035477\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it remained to place these values into the original equation to see if that equation holds true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it holds true for y = 5.000000001\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it also holds true for y = .5848035477\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the solution from the quadratic solver is shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i also solved the equation graphically as shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graphical solutions are rounded to 3 decimal places but they confirm the alebraic solutuion is correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in the graph, i used x instead of y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "same equation with a change in variable name.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the intersection of the 2 graphs is the solution, with the correct value of the original y being the x-coordinate of the coordinate pair.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for example, the coordinate pair of (.585,2) says that the value of x is .585.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you would simply read that as y = .585.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "similarly, the coordinate pair of (5,2) says that the value of x is 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you would simply read that as y = 5.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |