document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077090>Question 1077090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If an isosceles triangle has an apex angle of 45 degrees and 2 sides of 2.5 metres. what is the length of the base please?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691648 by </B><A HREF=/tutors/aboutme.mpl?userid=akch2002><B>akch2002(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=akch2002><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=akch2002><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691648\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sum of other remaining angles = 180-45 = 135 deg<BR>\n" );
document.write( "Hence, each angle = 135/2 = 67.5 deg<BR>\n" );
document.write( "Hence, base = 2.5cos67.5+2.5cos67.5 <BR>\n" );
document.write( "= 2*2.5cos67.5<BR>\n" );
document.write( "= 1.9134meters<BR>\n" );
document.write( "we can use cosine rule also.<BR>\n" );
document.write( "cos45=(2.5^2+2.5^2-base^2)/(2*2.5*2.5)<BR>\n" );
document.write( "solving it, we get base = 1.9134meters. </SPAN>\n" );
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