document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077086>Question 1077086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 3 is added to a three quarter of a certain number the result is 30. find the original number<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691646 by </B><A HREF=/tutors/aboutme.mpl?userid=amfagge92><B>amfagge92(93)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amfagge92><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amfagge92><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET THE NUMBER BE X<BR>\n" );
document.write( "3+3x/4=30<BR>\n" );
document.write( "multiply bothsides by 4<BR>\n" );
document.write( "12+12x=120<BR>\n" );
document.write( "subtract 12 from bothsides<BR>\n" );
document.write( "12x=108<BR>\n" );
document.write( "divde through by 12<BR>\n" );
document.write( "X=9.<BR>\n" );
document.write( "check:3x/4+3=30<BR>\n" );
document.write( "putting 9 for X<BR>\n" );
document.write( "3*9/4+3=30\r<BR>\n" );
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