document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077013>Question 1077013</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question 3 10.2.9-T<BR>\n" );
document.write( "Test the hypothesis using the P value approach. Be sure the verify the requirements of the test. <BR>\n" );
document.write( "H0:p=.46 versus H1: p<.46<BR>\n" );
document.write( "n= 150 x=63 &#945;=.01\r<BR>\n" );
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document.write( "I'm having a really hard time figuring out what p-value is  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691614 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a one sample proportion test.  If all the assumptions are correct, the critical value is |z|>2.576<BR>\n" );
document.write( "The proportion is 63/150, which is 0.42<BR>\n" );
document.write( "z=(0.42-0.46)/sqrt (.46*.54)/150; sqrt term=0.0407<BR>\n" );
document.write( "z=-0.04/0.0407=-0.9828<BR>\n" );
document.write( "From the table or a calculator the probability left of that z-value is 0.16, which is the p-value.  This is a one-way test, so it is not doubled.  One would not reject Ho<BR>\n" );
document.write( "I usually check these on the calculator, where a one sample proportion test is very easy to run. </SPAN>\n" );
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