document.write( "Question 1077037: How many gallons of a 10% salt solution must be mixed with 50 gallons of a 50% salt solution to obtain a 20% salt solution? \n" ); document.write( "

Algebra.Com's Answer #691603 by Boreal(15235) $\"\"$ $\"About$

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x=10%\r
\n" ); document.write( "\n" ); document.write( ".10(x)+.50(50)=.20(50+x)
\n" ); document.write( ".10x+25=10+.20x
\n" ); document.write( "-.10x=-15
\n" ); document.write( "x=150 gallons of 10% salt.
\n" ); document.write( "Check
\n" ); document.write( "To go from 50% to 20% is 3/4 of the way to 10%
\n" ); document.write( "150 gallons of the final 200 gallon mixture is 3/4 of the mixture.
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