document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1076979>Question 1076979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 times its width.  If the width is doubled and the length is increased by 1, the area is increased by 56.<BR>\n" );
document.write( " Represent the length in terms of the width:  Length = ______<BR>\n" );
document.write( "Represent the area of the original rectangle using w and the expression from part a.<BR>\n" );
document.write( "Area of original rectangle = ________________<BR>\n" );
document.write( "Represent the width of the new rectangle.  Width of new rectangle = _____<BR>\n" );
document.write( "Represent the length of the new rectangle.  Length of new rectangle = _______<BR>\n" );
document.write( "Represent the area of the new rectangle.  Area of the new rectangle = _________<BR>\n" );
document.write( "Distribute in the equation from part e to get a quadratic equation: ___________________<BR>\n" );
document.write( "Write the equation that compares the areas of the old and new rectangles:<BR>\n" );
document.write( "___________________________________= ________________________________<BR>\n" );
document.write( "Combine like terms and write the equation in standard form.<BR>\n" );
document.write( "___________________________________________________________<BR>\n" );
document.write( "a = _____    b = ______  c = _______<BR>\n" );
document.write( "Plug the values from part i into the quadratic formula:\r<BR>\n" );
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document.write( "Simplify and solve.  Show your work.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691574 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width is x, length ix 3x, area is 3x^2<BR>\n" );
document.write( "2x*(3x+1)=6x^2+2x, and subtract 56=3x^2, the original area<BR>\n" );
document.write( "3x^2+2x-56=0<BR>\n" );
document.write( "a=3, b=2, c=-56<BR>\n" );
document.write( "x=(1/6)(-2+/- sqrt(4+672)); sqrt 676=26<BR>\n" );
document.write( "x=(1/6)(24), take positive root only, and x=4<BR>\n" );
document.write( "width 4 <BR>\n" );
document.write( "length is 12<BR>\n" );
document.write( "area is 48<BR>\n" );
document.write( "width 8 and length 13, area is 104, which is 56 more.<BR>\n" );
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