document.write( "Question 1076973: A train leaves a station and travels north at a speed of 50 mph. Five hours​ later, a second train leaves on a parallel track and travels north at 175 mph. How far from the station will they​ meet?
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Algebra.Com's Answer #691545 by josmiceli(19441)\"\" \"About 
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Find the head start in miles for the 1st train
\n" ); document.write( "\"+d%5B1%5D+=+50%2A5+\"
\n" ); document.write( "\"+d%5B1%5D+=+250+\" mi
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\n" ); document.write( "Let \"+d+\" = distance in miles the 2nd train
\n" ); document.write( "travels until they meet
\n" ); document.write( "Let \"+t+\" = time in hrs after 2nd train leaves
\n" ); document.write( "until they meet
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\n" ); document.write( "Equation for 1st train:
\n" ); document.write( "(1) \"+d+-+250+=+50t+\"
\n" ); document.write( "Equation for 2nd train:
\n" ); document.write( "(2) \"+d+=+175t+\"
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\n" ); document.write( "Plug (2) into (1)
\n" ); document.write( "(1) \"+175t+-+250+=+50t+\"
\n" ); document.write( "(1) \"+125t+=+250+\"
\n" ); document.write( "(1) \"+t+=+2+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+=+175t+\"
\n" ); document.write( "(2) \"+d+=+175%2A2+\"
\n" ); document.write( "(2) \"+d+=+350+\"
\n" ); document.write( "They will meet 350 mi from the station
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\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+-+250+=+50t+\"
\n" ); document.write( "(1) \"+d+-+250+=+50%2A2+\"
\n" ); document.write( "(1) \"+d+=+250+%2B+100+\"
\n" ); document.write( "(1) \"+d+=+350+\"
\n" ); document.write( "OK
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