document.write( "Question 1076940: In a simple random sample of 19 gas stations in the Atlanta area, the price per gallon of regular gasoline has a mean of $2.12 and a (sample) standard deviation of $0.37. Use this sample data to find a 90% confidence interval for the mean price per gallon of all gas stations in the Atlanta area.\r
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document.write( "$___________<μ< $___________\r
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document.write( "The margin of error for this confidence interval is: $____________ \n" );
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Algebra.Com's Answer #691529 by Boreal(15235) You can put this solution on YOUR website! t=1.734, df=18 0.95 \n" ); document.write( "CI is mean +/- 1.734 s/sqrt(n) \n" ); document.write( "=2.12+/-1.734*0.37/sqrt(19), interval is 0.147, which is margin of error \n" ); document.write( "($1.97, $2.27) \n" ); document.write( " |