document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95037>Question 95037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 2x^2+5x-3=0 and x>0, then what is the value of x?\r<BR>\n" );
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document.write( "I'm having trouble with the test booklet explanation.\r<BR>\n" );
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document.write( "It indicates to factor (2x-1)(x-3)=0, but for some reason I am having trouble understanding what happens to the 5x. Maybe it is the factoring portion I am drawing a blank on. Please assist me with step by step details.  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69148 by </B><A HREF=/tutors/aboutme.mpl?userid=williacy><B>williacy(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=williacy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^2+5x-3=0\r<BR>\n" );
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document.write( "First you must factor 2x^2+5x-3:<BR>\n" );
document.write( "1.  Multiply the first and last coefficients:  2 x -3 = -6<BR>\n" );
document.write( "2.  Find two multiples of -6 that can be added to get 5.<BR>\n" );
document.write( "3.  The two multiples are 6 and -1  {6x-1=-6 and 6+(-1)=5}<BR>\n" );
document.write( "4.  Use the two multiples to help you write two binomials:  (x+6)(x+-1)<BR>\n" );
document.write( "5.  Since there is a 2 in front of the x^2 term, divide the 6 and -1 by the 2.  <BR>\n" );
document.write( "6.  You will have . . . (x + 3)(x + -1/2)<BR>\n" );
document.write( "7.  Since you should have all whole numbers and not fractions, take the 2 from the denominator and put it in front of the 2, and thus you will have the factored from of 2x^2+5x-3:<BR>\n" );
document.write( "   (x + 3)(2x + -1)\r<BR>\n" );
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document.write( "Now to solve:<BR>\n" );
document.write( "1.  Set each of the binomials to equal zero, and solve for x.<BR>\n" );
document.write( "x+3 = 0   x = -3\r<BR>\n" );
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document.write( "2x + -1 = 0  <BR>\n" );
document.write( "2x = 1<BR>\n" );
document.write( "x = 1/2\r<BR>\n" );
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document.write( " </SPAN>\n" );
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