document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1076835>Question 1076835</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Tracy and Klein  studied together for the midterm exam. It took them 4 3/4  hours from start to finish during this time they took a half hour break to eat lunch and two more breaks that were one third of an hour to get snacks what is the best estimate of the time that was spent studying? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691451 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691451\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4 3/4 -1/2 for lunch=4 1/4<BR>\n" );
document.write( "subtract 2(1/3)=2/3 from 4 1/4<BR>\n" );
document.write( "Can make it 4 3/12-8/12, using the common denominator of 12.  Borrow 5 from 12/12, and it is 3 7/12.<BR>\n" );
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document.write( "Subtracting 2/3 from 4 1/4<BR>\n" );
document.write( "Go the other way.<BR>\n" );
document.write( "from 2/3 to 1 you need 1/3<BR>\n" );
document.write( "From 1 to 4 you need 3<BR>\n" );
document.write( "from 4 to 4 1/4 you need 1/4<BR>\n" );
document.write( "3 +(1/3)+(1/4)=3 (4/12)+(3/12)=3 (7/12) </SPAN>\n" );
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