document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1076833>Question 1076833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given a cylinderical tin with radius of each cross section 3m and hight 6m. Calculate it's Surface Area.<BR>\n" );
document.write( "a. The two (2) ends are not clossed.<BR>\n" );
document.write( "b. One (1) end is closed.<BR>\n" );
document.write( "c. The two (2) ends are closed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691448 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691448\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given a cylinderical tin with radius of each cross section 3m and hight 6m. Calculate it's Surface Area.<BR>\n" );
document.write( "a. The two (2) ends are not closed.<BR>\n" );
document.write( "Ans:: S = 2*pi*r*h = 2pi*3*6 = 36pi sq. meters<BR>\n" );
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document.write( "b. One (1) end is closed.<BR>\n" );
document.write( "Ans:: S + pi*3^2 = 36pi+ 9pi = 45pi sq meters<BR>\n" );
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document.write( "c. The two (2) ends are closed.<BR>\n" );
document.write( "Ans:: S + 2(pi)*9 = 45+9pi = 54pi sq meters<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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