document.write( "Question 1076712: Please show me how to solve the triangle of B = 130°, c = 10.1, b = 5.2
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Algebra.Com's Answer #691350 by KMST(5328)\"\" \"About 
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That is an impossible triangle.
\n" ); document.write( "Maybe there is a typo.
\n" ); document.write( "Otherwise, you are expected to say that the triangle is impossible.
\n" ); document.write( "You know that in any triangle,
\n" ); document.write( "a longer side is opposite a larger angle.
\n" ); document.write( "In the problem you posted, \"c%3Eb\" ,
\n" ); document.write( "so for the angles, it should be \"C%3EB\" ,
\n" ); document.write( "but \"B=130%5Eo\" , so the triangle cannot have another larger angle.
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\n" ); document.write( "IN GENERAL:
\n" ); document.write( "When a triangle is not a right triangle, you can use
\n" ); document.write( "Law of sines (easier if applicable) or
\n" ); document.write( "Law of cosines.
\n" ); document.write( "You know that in a triangle
\n" ); document.write( "the largest angle is the one opposite the longest side.
\n" ); document.write( "Law of done goes further and tells you that
\n" ); document.write( "the sine of an angle is proportional to the length of the opposite side.
\n" ); document.write( "As a formula, you can write it as
\n" ); document.write( "\"sin%28A%29%2Fa=sin%28B%29%2Fb=sin%28C%29%2Fc\" or \"a%2Fsin%28A%29=b%2Fsin%28B%29=c%2Fsin%28C%29\" .
\n" ); document.write( "If you have the measure of one angle (such as C),
\n" ); document.write( "and the length of the opposite side (such as c),
\n" ); document.write( "along with one other measurement of the triangle (such as b),
\n" ); document.write( "you can use Law of sines.
\n" ); document.write( "In that case,
\n" ); document.write( "\"sin%28C%29%2Fc=sin%28B%29%2Fb\"
\n" ); document.write( "would allow you to calculate the approximate value for
\n" ); document.write( "\"sin%28C%29=c%2Ason%28B%29%2Fb\" .
\n" ); document.write( "In general, the value for the \"sin%28C%29\" you found
\n" ); document.write( "could correspond to an acute angle,
\n" ); document.write( "or to the supplementary obtuse angle.
\n" ); document.write( "There are some cases where the answers would be two triangles.
\n" ); document.write( "However, there can be at most one obtuse angle.
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