document.write( "Question 1076664: Hello, I'm about to take the ASTB-E and have been studying some gouge. One problem that came up was\r
\n" ); document.write( "\n" ); document.write( "(4^-1/4 - 16^-3/9) / 2^-5/10\r
\n" ); document.write( "\n" ); document.write( "How do I hand jam this (without calculator) problem, or does it seem a little unrealistic for a standardized test that is timed?
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Algebra.Com's Answer #691307 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
(4^-1/4 - 16^-3/9) / 2^-5/10
\n" ); document.write( "------
\n" ); document.write( "= (2^-1/2 - 16^-1/3) / 2^-1/2
\n" ); document.write( "Multiply by 2^(1/2)
\n" ); document.write( "= 1 - (16^-1/3)*2^(1/2)
\n" ); document.write( "= 1 - (2^-1/3)*8^(-1/3)*2^(1/2)
\n" ); document.write( "= 1 - sqrt(2)/(2^1/3)*8^(1/3)
\n" ); document.write( "= 1 - sqrt(2)/2(2^1/3)\r
\n" ); document.write( "\n" ); document.write( "= \"1+-++sqrt%282%29%2F2root%283%2C2%29\"
\n" ); document.write( "= \"1+-++root%286%2C8%29%2F2root%286%2C4%29\"
\n" ); document.write( "= \"1+-++root%286%2C2%29%2F2\"
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