document.write( "Question 1076664: Hello, I'm about to take the ASTB-E and have been studying some gouge. One problem that came up was\r
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document.write( "(4^-1/4 - 16^-3/9) / 2^-5/10\r
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document.write( "How do I hand jam this (without calculator) problem, or does it seem a little unrealistic for a standardized test that is timed? \n" );
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Algebra.Com's Answer #691307 by Alan3354(69443) You can put this solution on YOUR website! (4^-1/4 - 16^-3/9) / 2^-5/10 \n" ); document.write( "------ \n" ); document.write( "= (2^-1/2 - 16^-1/3) / 2^-1/2 \n" ); document.write( "Multiply by 2^(1/2) \n" ); document.write( "= 1 - (16^-1/3)*2^(1/2) \n" ); document.write( "= 1 - (2^-1/3)*8^(-1/3)*2^(1/2) \n" ); document.write( "= 1 - sqrt(2)/(2^1/3)*8^(1/3) \n" ); document.write( "= 1 - sqrt(2)/2(2^1/3)\r \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( " \n" ); document.write( " |