document.write( "Question 1076426: There is a small island in the middle of a 100m wide river and a tall tree
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Algebra.Com's Answer #691295 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
let T equal the top of the tree and B equal the bottom of the tree.\r
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\n" ); document.write( "\n" ); document.write( "you have 2 triangles formed with a common side being side TB\r
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\n" ); document.write( "\n" ); document.write( "the first triangle formed is PTB with angle P equal to 30 degrees.\r
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\n" ); document.write( "\n" ); document.write( "the second triangle formed is QTB with angle Q eaual to 45 degrees.\r
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\n" ); document.write( "\n" ); document.write( "both triangle PTB and QTB are part of the overall triangle formed of PTQ.\r
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\n" ); document.write( "\n" ); document.write( "TB is assumed to be perpendicular to PQ.\r
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\n" ); document.write( "\n" ); document.write( "therefore triangles PTB and QTB are assumed to be right triangles.\r
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\n" ); document.write( "\n" ); document.write( "you are given that the length of PQ is equal to 100 meters.\r
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\n" ); document.write( "\n" ); document.write( "tan(30) = TB / PB\r
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\n" ); document.write( "\n" ); document.write( "tan(45) = TB / BQ\r
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\n" ); document.write( "\n" ); document.write( "solve for TB in both these formulas to get:\r
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\n" ); document.write( "\n" ); document.write( "TB = PB * tan(30)\r
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\n" ); document.write( "\n" ); document.write( "TB = BQ * tan(45)\r
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\n" ); document.write( "\n" ); document.write( "since they are both equal to TB, then you get:\r
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\n" ); document.write( "\n" ); document.write( "PB * tan(30) = BQ * tan(45)\r
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\n" ); document.write( "\n" ); document.write( "let x equal the length of PB.\r
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\n" ); document.write( "\n" ); document.write( "therefore 100 - x equals the length of BQ.\r
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\n" ); document.write( "\n" ); document.write( "the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "x * tan(30) = (100 - x) * tan(45)\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "x * tan(30) = 100 * tan(45) - tan(45) * x\r
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\n" ); document.write( "\n" ); document.write( "add tan(45) * x to both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x * tan(30) + x * tan(45) = 100 * tan(45)\r
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\n" ); document.write( "\n" ); document.write( "factor out the x to get:\r
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\n" ); document.write( "\n" ); document.write( "x * (tan(30) + tan(45)) = 100 * tan(45)\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by (tan(30) + tan(45)) to get:\r
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\n" ); document.write( "\n" ); document.write( "x = (100 * tan(45) / (tan(30) + tan(45))\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get:\r
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\n" ); document.write( "\n" ); document.write( "x = 63.39745962\r
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\n" ); document.write( "\n" ); document.write( "that's the length of PB.\r
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\n" ); document.write( "\n" ); document.write( "100 - x = 36.60254038\r
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\n" ); document.write( "\n" ); document.write( "that's the length of BQ\r
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\n" ); document.write( "\n" ); document.write( "you were asked to find the distance of p from the tree.\r
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\n" ); document.write( "\n" ); document.write( "that would be the length of PB.\r
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\n" ); document.write( "\n" ); document.write( "TB is the height of the tree and that turns out to be 36.60254038 meters.\r
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\n" ); document.write( "\n" ); document.write( "your diagram would look like this:\r
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