document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1076641>Question 1076641</A>: <I><SPAN STYLE=\"word-break: break-all;\"> tan a+cot a =seca.coseca </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #691282 by </B><A HREF=/tutors/aboutme.mpl?userid=Herdaysoji><B>Herdaysoji(25)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Herdaysoji><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Herdaysoji><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=691282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> tanA+cotA=secA.cosecA<BR>\n" );
document.write( "I.e; tanA=(sinA/cosA) and cotA=(1/tanA)<BR>\n" );
document.write( ".'.tanA+cotA=(sinA/cosA)+(1/(sinA/cosA)<BR>\n" );
document.write( ".'.(sinA/cosA)+(cosA/sinA)<BR>\n" );
document.write( "    L.C.M<BR>\n" );
document.write( "   sin^2A+cos^2A/(cosA.sinA)<BR>\n" );
document.write( " but.never forget your trigonometry identity that (sin^2A+cos^2A=1)<BR>\n" );
document.write( ".'.(1/cosA)*(1/sinA)=1/(cosA.sinA)=secA.cosecA </SPAN>\n" );
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